함수를 return 하거나 new line 없이 printf를 실행할 때 segmentation fault가 뜹니다.

Question

안녕하세요. 다음과 같은 함수를 만들었습니다.printf(&#34;hello
&#34;)와 같이 new line이 있는 printf는 잘 작동합니다.하지만 printf(&#34;hello&#34;)처럼 new line이 없으면 segmentation fault가 발생합니다.printf를 다 지우고 return;을 넣어도 segmentation fault가 뜹니다... 대체 왜 이런건가요?몇몇 글을 보니 heap memory가 overwritten 됐을 때 나오는 경우라 하는데 제 코드에서는 overwritten될 기미가 있는 곳이 안 보여서요...ㅠㅠ 도와주세용...void parse_uri(request * req, char * buf){//method, uri(host&#43;port), version printf(&#34;parse_uri
&#34;); char method[10]; char uri[MAXLINE]; char version[MAXLINE]; sscanf(buf, &#34;%s %s %s&#34;, method, uri, version); strcpy(req->method,method);strcpy(req->uri,uri);strcpy(req->version,version); char *host_start;char *port_start; char *port_end; char *path;char *port&#61;&#34;3000&#34;; host_start&#61;strstr(uri, &#34;http://&#34;); if (host_start&#61;&#61;NULL){ (req->host)[0]&#61;&#34;\0&#34;; return; //bad request } host_start&#43;&#61;7; //http://abce-> abce.. port_start&#61;strstr(host_start, &#34;:&#34;); path&#61;strstr(host_start, &#34;/&#34;); printf(&#34;(%s)'s address: %p, (%s)'s address: %p 
&#34;, port_start, port_start, path, path); size_t hostlen, portlen; if (!port_start){ //no port if (!path){ //no path strcpy(req->host, host_start); strcpy(req->path, &#34;/&#34;); } else{ hostlen&#61;path-host_start; (req->host)[0]&#61;&#34;\0&#34;; strncpy(req->host, host_start, hostlen); strcpy(req->path, path); } strcpy(req->port, port); //default 3000 } else{//port exists printf(&#34;port O
&#34;); (req->host)[0]&#61;&#34;\0&#34;; hostlen&#61;port_start-host_start; strncpy(req->host, host_start, hostlen); printf(&#34;req->host: %s
&#34;, req->host); if (!path){ strcpy(req->port, port_start&#43;1); //GET http://localhost:8000 strcpy(req->path, &#34;/&#34;); } else{ //GET http://localhost:8000/path printf(&#34;path O
&#34;); portlen&#61;path-(port_start&#43;1);//port_start&#61;&#34;:~&#34;, path&#61;&#34;/~&#34; strncpy(req->port, port_start&#43;1,portlen); printf(&#34;req->port: %s 
&#34;, req->port); strcpy(req->path, path); printf(&#34;err
&#34;); } } printf(&#34;hello
&#34;); printf(&#34;hello&#34;); }

함수를 return 하거나 new line 없이 printf를 실행할 때 segmentation fault가 뜹니다.

0개의 답변

#segmentation 목록