jpa repository 메소드명으로 데이터 찾기 질문이요

Question

테스트코드 @Test public void findByUsernameAndAgeGreaterThan(){ Member m1 = new Member("AAA",10); Member m2 = new Member("BBB",30); memberRepository.save(m1); memberRepository.save(m2); List members = memberRepository.findAll(); System.out.println("*********members"+members); List result = memberRepository.findByUsernameAndAgeGreaterThan("AAA",10); if(result.isEmpty()){ System.out.println("NULL"); }else{ System.out.println("*********result "+result); assertThat(result.get(0).getUsername()).isEqualTo("AAA"); assertThat(result.get(0).getAge()).isEqualTo(10); } }repository List findByUsernameAndAgeGreaterThan(String username,int age); Entity@Entity @Getter @NoArgsConstructor(access = AccessLevel.PROTECTED) @ToString(of= {"id","username","age"}) public class Member { @Id @GeneratedValue @Column(name ="member_id") private Long id; @Column(name ="user_name") private String username; private int age; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "team_id") private Team team; public Member(String name) { this.username = name; } public Member(String username, int age) { this.username = username; this.age = age; } public Member(String username, int age, Team team) { this.username=username; this.age=age; if( team!=null){ changeTeam(team); }else{ System.out.println("Team null"); } } public void changeUserName(String name){ this.username = name; } public void changeTeam(Team team){ this.team= team; team.getMembers().add(this); } }값이 실제로 있는데 result의 list값이 null입니다왜 값을 못찾는건가요??

쿡쿠 · Answer

GreaterThanEqual

코미 · Answer

음..똑같이 해 봤는데 저는 잘 되네요.메소드 이름 자체는 문제 없어 보여요

jpa repository 메소드명으로 데이터 찾기 질문이요

2개의 답변

#repository 목록